respectively. What horizontal pushing pressure is required to (a) just start the crate moving and (b) on slide the crate across the dock at continuous speed
\"*\"

The horizontal pushing force required to just start the crate relocating is 447 N.

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The horizontal pushing force required to on slide the crate throughout the dock at a continuous speed is 241 N.

Explanation:

By the an interpretation of the coefficient of static friction we have:

μ

\"*\"
=
\"*\"
,

where,

\"*\"
is the horizontal pushing force,

W = mg is the weight the the crate directed downward,

\"*\"
is the static friction force-directed opposite to the horizontal advertise force and also equal come it,

N is the force of reaction directed upward and also equal to the weight of the crate.

From this formula us can uncover the horizontal pushing pressure required to just start the crate moving:

\"*\"

= 0.760

\"*\"
60 kg
\"*\"
9.8 m / s^2

= 447 N.

By the definition the the coefficient of kinetic friction we have:

u

\"*\"
,

where,

\"*\"
is the horizontal advertise force,

W = mg is the weight of the crate directed downward,

\"*\"
is the kinetic friction force-directed opposite come the horizontal pushing force and equal to it,

N is the force that reaction command upward and equal come the load of the crate.

From this formula we can discover the horizontal pushing force required to on slide the crate throughout the dock in ~ a consistent speed:

\"*\"

= 0.410

\"*\"
60
\"*\"
9.8

= 241 N.

The horizontal pushing pressure required to simply start the crate moving is 447 N.

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The horizontal pushing pressure required to slide the crate throughout the dock at a constant speed is 241 N.