Presentation on theme: "How plenty of Skittles room In a 2.17 ounce Bag? By: Ryan Riling & Tom Dougherty."— Presentation transcript:




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2 How many Skittles room In a 2.17 oz Bag? By: Ryan Riling & Tom Dougherty

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3 HistoryHistory -Skittles production originated in England -First presented to United claims in 1974 -Owned by Mars Inc. -Skittles factory are situated in U.S, Victoria, Australia, and new Zealand -Advertising projects are linked with rainbows -“Taste the Rainbow”

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4 PurposePurpose -We wanted to identify whether or no Mars Inc. (producer that Skittles) was relatively filling your bags with the declared amount. -We decided to acquisition 35 standard sized bags of cones (2.17 ounce) and also test to determine if Skittles consumer are acquiring their money’s worth.

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5 sleeve Stores -Acme  5 2.17 oz. Bags -Genuardi’s  5 2.17 oz. Bags -Giant  5 2.17 oz. Bags -Redner’s  5 2.17 oz. Bags -CVS  five 2.17 oz. Bags -Wawa  5 2.17 oz. Bags -7-11  five 2.17 oz. Bags complete = 35 BAGS

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6 DataData

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7 GraphsGraphs

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8 Graphs (Cont.) 5254565860626466687072 five Number an introduction Minimum = 53 Quartile 3 = 63 Quartile 1 = 56 maximum = 68 average = 59 number of Skittles

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9 Stem Plot 5 53 54 5 5 5 56 6 6 6 7 7 7 7 58 8 8 9 9 9 9 9 9 60 62 2 2 3 3 3 64 4 5 66 6 68 shape = about Symmetric facility = 59 spread = Minimum – 53 maximum – 68

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10 1 Var Stats x = 59.4286 Σx = 2080 Σx² = 124110 Sx = 3.8293 n = 35 Minimum = 53 Quartile 1 = 56 mean = 59 Quartile 3 = 63 preferably = 68

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11 presumptions 1). SRS 1). 2). Normal population 2). 35 ≥ 30 OR n ≥ 30

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12 HypothesisHypothesis -Ho:  = 60 skittles per 2.17 oz. Bag -Ha:  ≠ 60 cones per 2.17 oz. Bag

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) =.3835 degrees Freedom: Df = n-1 =" > 13 TestsTests One Sample T-Test test Statistic: t* = x - µ s/ √n = P-Value: 2 * P(µ > -.8828) =.3835 levels Freedom: Df = n-1 = 34 -.8828

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) =.3835 levels Freedom: Df = n-1 =" title="TestsTests One Sample T-Test check Statistic: t* = x - µ s/ √n = P-Value: 2 * P(µ > ) =.3835 levels Freedom: Df = n-1 =">

14 test (Cont.) Conclusion: we fail to reject the null hypothesis because our p-value is better than  =.05. Us have adequate evidence that the mean variety of Skittles per 2.17 oz. Bag is 60 Skittles.

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15 confidence Level (95%) trust Level = x ± t*(s/ √ n) = (58.113, 60.744) We are 95% Confident that the mean variety of Skittles every 2.17 oz. Bag is in between 58.113 and 60.744 Skittles.

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16 an individual Opinions -We felt as though it was really tedious to counting the amount of cones in each of the 35 bags -It was time-consuming to travel to every of the 7 stores to acquire the forced amount the samples -We agree v our T-Test results and also feel as though where ever before you choose to buy her Skittles from, friend are getting a same amount per bag because that the price.

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17 ApplicationApplication -Although large had the biggest average variety of Skittles every bag, we feel as though it is unnecessary to go the end of your means just to buy skittles at Giant. -We feel together though Mars Inc. Fairly manufactures and also packages their Skittles bags.

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- 7-11 skittles bags are packaged most fairly and have an average of 60.2 skittles per bag.

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18 Bias/ErrorBias/Error -Incorrect Skittles counting -Mistake entering data into lists -Obtaining cones at various stores  chose the an initial available bags -Counting broken or deformed cones

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