You are watching: Chemical formula for lead iv nitrate
This is the solution in the answer sheet (left side of the equal authorize is the question, and also the ideal side is the answer)
lead(III) oxide = command (IV) oxide
Pb(NO$_3$)$_3$ = Pb(NO$_3$)$_2$
iron oxide = iron (II) oxide
dihydrogen oxide = hydrogen oxide
To take among those examples, I understand that lead exists both together lead (II) and lead (IV). Would certainly it be wrong to exactly the an initial name to command (II) oxide rather than lead (IV) oxide?
Can ns make comparable cases because that $\cePb(NO3)4$, stole (III) oxide, and also dihydrogen monoxide
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edited Jun 10 "20 in ~ 14:04
inquiry Dec 10 "16 in ~ 20:14
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Yes, your question is naturally unclear. Except for one, all of your compounds can be wrong in much more ways than one. Here’s how:
Obviously, lead(III) is not a secure oxidation state that lead; these are lead(II) and lead(IV). However, there space at three different, an extremely common command oxides (and potentially also more):lead(IV) oxide $\cePbO2$ (black)lead(II,IV) oxide, additionally called the command spinell, $\cePb3O4$ (orange)lead(II) oxide $\cePbO$
Due to their colours, they were commonly referred to together German flag in qualitative inorganic evaluation in Munich. Without extr information, the is not possible to identify which command oxide is meant.
Only one lead nitrate is known, to the ideal of mine knowledge; hence $\cePb(NO3)4$ would be invalid. I do not know why, though, due to the fact that both nitrate and lead(IV) must be oxidising agents and thus in principle able come combine.
The same problem with lead, only worse:iron(II) oxide $\ceFeO$ (black)iron(III) oxide $\ceFe2O3$ (red)Wikipedia perform six various iron(II,III) oxides, ranging from $\ceFe3O4$ (the steel spinell) to $\ceFe25O32$.
Hydrogen oxide, the prize sheet’s solution, need to actually be marked unclear.
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Dihydrogen oxide clearly refers to water $\ceH2O$, yet water is not the just hydrogen oxide. The distinction here when compared to the previous answers is the it is the oxidation state that oxygen which now varies: $\ceH2O2$ can be referred to as dihydrogen dioxide. And also in the very same vein in which various other $\ceA2B2$ compounds lose their number designators, hydrogen oxide might also refer come the $1:1$ link $\ceH2O2$. Ns doubt the was the price sheet’s intention, though; since dihydrogen oxide is unambiguous.