times a very first number. A third number is 100 much more than the first number. If the sum of the 3 numbers is

418418​,

find the numbers.

You are watching: The sum of 100 and four times a number

To occupational this sort of problem, must choose a change to represent the an initial number. How around "N".

Let N it is in the an initial number.

2nd number = 4 * the an initial number, so

2nd number = 4N

3rd number = 100 an ext than the first number, so

3rd number = N + 100

The amount of all three numbers is 418, for this reason we add all that these

N + 4N + N+100 = 418

Combine choose terms

6N + 100 = 418

Subtract 100 indigenous both sides

6N = 318

Divide both political parties by 6

N = 53

So...

1st number = 53

2nd number = 4 * 53 = 212

3rd number = 100 + 53 = 153

And come check, include these to be certain they total 418 (and they do!)

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