I have a graph with provided formulas wherein I have to determine, 1: Electron dot structure, 2: Total variety of electron groups, 3: Electron Geometry, 4: shortcut Angle, 5: number of Bonded Atoms, 6: molecular Geometry, and 7: Polar or Nonpolar.

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The formula ns am currently working top top is SBr2, I placed S in the middle and Br top top either next in a straight structure. Both Br's and also S have actually 8 electrons. When it asks the number of electron groups, is it asking how plenty of electron pairs space being shared? In this situation 2?

I think I'm ok with drawing the electron period structure and Polarity yet questions 2-6 i am having actually trouble with. The publication shows an example but doesn't describe how it acquired there. Any type of tips?

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level 1
· 6y
SBr2's shape (molecular geometry- I'm assuming) is angular/bent due to the repulsion of the two lone pairs. The electron geometry have to be tetrahedral.

Did you use the VSPER theory to attract the molecule first?

level 2
Op · 6y

Ok I check out the VSPER and also am now acquiring somewhere. I'm a bit puzzled though since if we are counting the number of electron teams surrounding the central atom (ex. :O=C=O: is under main atoms through 2 electron teams which i get) but then why is H20 Under 4 electron groups? that counts the lone pairs but doesn't O=C=O have actually lone pairs too?

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level 1
· 6y
I think you've acquired it sorted but I figured I'd add this simply in case.

Total variety of electron groups way the variety of bonds and also lone pairs roughly the main atom, yet counting twin and triple bonds as 1 \"electron group\".

In SBr*2* this is 4, 2 S-Br bonds and also 2 lone bag = 4.

In BH*3* this is 3, 3 B-H bonds.

Electron geometry is the geometry of all of the electron groups around the main atom.

In SBr*2* there are 4 groups so that is tetrahedral.

In BH*3* there room 3 teams so it is trigonal planar.

2 = linear, 5 = trigonal bipyramidal, etc.

Bond angle come native the electron geometry, although i don't think they want you to actually calculate it simply estimate it based upon the geometry.

SBr*2* has a tetrahedral electron geometry and tetrahedral bond angles room ~109.5°. But SBr*2* likewise has 2 lone pairs which pushes the Br-S-Br bond angle closer together, Google will certainly tell girlfriend the specific number yet

Number of bonded atoms is directly forward.

Molecular geometry is the geometry of the external inspection atoms.

SBr*2* has 4 electron groups, however only 2 that them space in chemical bonds. You've probably seen a table of every one of the names favor this. If girlfriend look under tetrahedral geometry, 2 bonding areas + 2 lone bag you'll see the molecule geometry is \"bent\".

BH*3* has 3 electron groups and also 3 chemical bonds, look at the exact same table and also the name is the exact same as the electron geometry, trigonal planar.

Polar or no polar is interesting. You've claimed you know it however I'll simply remind friend if you already know that not all polar bonds result in polar molecules.

The C-O bond is polar because there's an electronegativity difference between C and also O, yet CO*2* is a no polar molecule due to the fact that there is no network dipole as the molecule is symmetrical. Both dipoles cancel and also the an outcome is no overall dipole.

Same v the C-Cl shortcut in CCl*4*, no network dipole due to the fact that the molecule is symmetrical.

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H*2*O is a polar molecule due to the fact that the 2 lone pairs on oxygen typical the molecule is non symmetrical.