Copper has actually an electron construction of $ce 3d^10 4s^1$. Now sometimes the noble state is written as $ce 3d^10 4s^1$ or together $ce 4s^2 3d^9$.

You are watching: Using noble gas notation write the electron configuration for the copper(i) ion.

Now the an initial noble state appears to be the exact same as his regular configuration and the last seems to have actually equal electrons yet divided in an additional way.

Now copper has actually two oxidation numbers $+1$ and also $+2$ and also as copper is d-element of the $4$ duration it follows the $18$-electrons rule. However probably the $18$ electron aren"t developed to gain the krypton noble state. So how does the noble state configuration of copper work?


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$ce 4s^1 3d^10$ is the correct configuration for copper. Why?

In easiest terms, some elements do not follow the Aufbau principle, therefore there space some alternating ways that electrons have the right to arrange us that offer these elements better stability.

Copper is a transition element and shift elements like either half fill orbitals or fully-filled orbitals. This makes them more stable.

For example:

Using the Aufbau principle, you would certainly write the adhering to electron configurations:

$ceCr = 4s^2 3d^4$$ceCu = 4s^2 3d^9$

However, the yes, really electron configuration are:

$ceCr = 4s^1 3d^5$$ceCu = 4s^1 3d^10$
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